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Interview Questions, Answers and Tutorials

Java If-Else

Java If-Else

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In this challenge, we test your knowledge of using if-else conditional statements to automate decision-making processes. An if-else statement has the following logical flow:

Wikipedia if-else flow chart

Source: Wikipedia

Task
Given an integer, n, perform the following conditional actions:

  • If n is odd, print Weird
  • If n is even and in the inclusive range of 2 to 5, print Not Weird
  • If n is even and in the inclusive range of 6 to 20, print Weird
  • If n is even and greater than 20, print Not Weird

Complete the stub code provided in your editor to print whether or not n is weird.

Input Format

A single line containing a positive integer, n.

Constraints

  • 1 <= n <= 100

Output Format

Print Weird if the number is weird; otherwise, print Not Weird.

Sample Input 0

3

Sample Output 0

Weird

Sample Input 1

24

Sample Output 1

Not Weird

Explanation

Sample Case 0: n = 3
n is odd and odd numbers are weird, so we print Weird.

Sample Case 1: n = 24
n>20 and n is even, so it isn’t weird. Thus, we print Not Weird.

Solution:

import java.io.*;
import java.math.*;
import java.security.*;
import java.text.*;
import java.util.*;
import java.util.concurrent.*;
import java.util.regex.*;

public class Solution {

    private static final Scanner scanner = new Scanner(System.in);

    public static void main(String[] args) {
        int N = scanner.nextInt();
        scanner.skip("(\r\n|[\n\r\u2028\u2029\u0085])?");

        scanner.close();
        
        if(N%2==0 && N>=2 && N<=5){
            System.out.println("Not Weird");
        }
        else if(N%2==0 && N>=6 && N<=20){
            System.out.println("Weird");
        }
        else if(N%2==0 && N>20){
            System.out.println("Not Weird");
        }
        else{
            System.out.println("Weird");
        }
    }
}