[email protected]
Interview Questions, Answers and Tutorials

Lists

Lists

HackerRanktestinganswers.com

Consider a list (list = []). You can perform the following commands:

  1. insert i e: Insert integer e at position .
  2. print: Print the list.
  3. remove e: Delete the first occurrence of integer e.
  4. append e: Insert integer e at the end of the list.
  5. sort: Sort the list.
  6. pop: Pop the last element from the list.
  7. reverse: Reverse the list.

Initialize your list and read in the value of n followed by n lines of commands where each command will be of the 7 types listed above. Iterate through each command in order and perform the corresponding operation on your list.

Example
N = 4
append 1
append 2
insert 3 1
print

  • append 1: Append  to the list, arr = [1].
  • append 2: Append  to the list, arr = [1, 2].
  • insert 3 1: Insert  at index , arr = [1, 3, 2].
  • print: Print the array.

Output:
[1, 3, 2]

Input Format

The first line contains an integer, n, denoting the number of commands.
Each line i of the n subsequent lines contains one of the commands described above.

Constraints

  • The elements added to the list must be integers.

Output Format

For each command of type print, print the list on a new line.

Sample Input 0

12
insert 0 5
insert 1 10
insert 0 6
print
remove 6
append 9
append 1
sort
print
pop
reverse
print

Sample Output 0

[6, 5, 10]
[1, 5, 9, 10]
[9, 5, 1]

Solution:

if __name__ == '__main__':
    N = int(input())
    newList = []
    
    for i in range(N):
        arr = list(input().split(" "))
        
        if arr[0] == "insert":
            newList.insert(int(arr[1]), int(arr[2]))

        elif arr[0] == "print":
            print(newList)
            
        elif arr[0] == "remove":
            newList.remove(int(arr[1]))

        elif arr[0] == "append":
            newList.append(int(arr[1]))

        elif arr[0] == "sort":
            newList.sort()

        elif arr[0] == "pop":
            newList.pop()

        elif arr[0] == "reverse":
            newList.reverse()