Python If-Else
Task
Given an integer, n, perform the following conditional actions:
- If n is odd, print
Weird
- If n is even and in the inclusive range of 2 to 5, print
Not Weird
- If n is even and in the inclusive range of 6 to 20, print
Weird
- If n is even and greater than 20, print
Not Weird
Input Format
A single line containing a positive integer, n.
Constraints
- 1 < n < 100
Output Format
Print Weird
if the number is weird. Otherwise, print Not Weird
.
Sample Input 0
3
Sample Output 0
Weird
Explanation 0
n = 3
n is odd and odd numbers are weird, so print Weird
.
Sample Input 1
24
Sample Output 1
Not Weird
Explanation 1
n = 24
n > 20 and n is even, so it is not weird.
Solution:
#!/bin/python3
import math
import os
import random
import re
import sys
if __name__ == '__main__':
n = int(input().strip())
if n % 2 == 0 and n in range(2,5):
print("Not Weird")
elif n % 2 == 0 and n in range(6, 20):
print("Weird")
elif n % 2 == 0 and n > 20:
print("Not Weird")
else:
print("Weird")